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Posted by Rudy on Wednesday, December 5, 2012 at 1:26am.
the slope of the line tangent to the curve y=(tanx/cosx) at x=(pi/3) is? a)-8 b)2√3 c)3√2 d)8 e)14
y'(x) = (sec^2*cos + tan*sin)/cos^2 y'(pi/3) = (4*(1/2) + √3 * √3/2)/(1/4) = 14
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