Posted by **Ann** on Tuesday, December 4, 2012 at 9:51pm.

Write an equation of a line perpendicular to y=2x+3 and passes through (3,4).

- Algebra URGENT -
**Mac**, Tuesday, December 4, 2012 at 10:28pm
Slope of the given line is 2 , therefore the slope of the perpendicular line is -(1/2)

Use your point slope equation y -y =m(x - x)

Y - 4 = -(1/2)(x - 3)

2(y - 4) = -1(x - 3). You are looking a proportion and cross multiplying

2y - 8 = -1x + 3

2y. =. -1x + 11

y. = -(1/2)x + (11/2)

- Algebra URGENT -
**Reiny**, Wednesday, December 5, 2012 at 12:08am
perpendicular to y = 2x + 3 implies the new equation must be

y = (-1/2)x + b

sub in the point (3,4)

4 = (-1/2)(3) + b

b = 4 + 3/2 = 11/2

y = (-1/2)x + 11/2

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