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Posted by on Tuesday, December 4, 2012 at 9:51pm.

Write an equation of a line perpendicular to y=2x+3 and passes through (3,4).

  • Algebra URGENT - , Tuesday, December 4, 2012 at 10:28pm

    Slope of the given line is 2 , therefore the slope of the perpendicular line is -(1/2)
    Use your point slope equation y -y =m(x - x)

    Y - 4 = -(1/2)(x - 3)
    2(y - 4) = -1(x - 3). You are looking a proportion and cross multiplying
    2y - 8 = -1x + 3
    2y. =. -1x + 11
    y. = -(1/2)x + (11/2)

  • Algebra URGENT - , Wednesday, December 5, 2012 at 12:08am

    perpendicular to y = 2x + 3 implies the new equation must be
    y = (-1/2)x + b

    sub in the point (3,4)
    4 = (-1/2)(3) + b
    b = 4 + 3/2 = 11/2

    y = (-1/2)x + 11/2

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