What is the molarity of a sulfuric acid solution if 30.00mL of H2SO4 is required to neutralize 0.840g of sodium hydrogen carbonate?

H2SO4(aq) + NaHCO3(aq) → Na2SO4(aq) + H2O(l)+ CO 2(aq)

Don't EVER write an equation without balancing it.

H2SO4 + 2NaHCO3 ==> Na2SO4 + 2H2O + 2CO2
mols NaHCO3 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols NaHCO3 of mols H2SO4. That will be
? mols NaHCO3 x (1 mol H2SO4/2 mol NaHCO3)= xx.
Then M H2SO4 = mols H2SO4/L H2SO4.

To find the molarity of the sulfuric acid (H2SO4) solution, we need to know the number of moles of H2SO4 and the volume of the solution.

1. Calculate the number of moles of sodium hydrogen carbonate (NaHCO3) using its molar mass:

number of moles = mass / molar mass
number of moles = 0.840g / (22.99g/mol + 1.01g/mol + 12.01g/mol + 3(16.00g/mol))
number of moles = 0.840g / 84.01g/mol
number of moles ≈ 0.01 mol

2. In the balanced equation, we can see that the stoichiometric ratio between H2SO4 and NaHCO3 is 1:1. This means that 1 mole of H2SO4 reacts with 1 mole of NaHCO3. So, the number of moles of H2SO4 will also be approximately 0.01 mol.

3. Convert the given volume of H2SO4 solution (30.00 mL) to liters:

volume = 30.00 mL * (1 L / 1000 mL)
volume = 0.03000 L

4. Calculate the molarity (M) using the formula:

molarity = number of moles / volume (in liters)
molarity = 0.01 mol / 0.03000 L
molarity ≈ 0.33 M

Therefore, the molarity of the sulfuric acid solution is approximately 0.33 M.

To find the molarity (M) of a sulfuric acid solution, we need to first calculate the number of moles of sulfuric acid (H2SO4), and then divide it by the volume of the solution in liters.

Step 1: Calculate the number of moles of sodium hydrogen carbonate (NaHCO3) using its molar mass.

The molar mass of sodium hydrogen carbonate (NaHCO3) is:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol

So, the molar mass of NaHCO3 is:
(1 x 22.99) + (1 x 1.01) + (1 x 12.01) + (3 x 16.00) = 84.01 g/mol

To find the number of moles of NaHCO3, we divide its mass by its molar mass:
0.840 g / 84.01 g/mol = 0.01 mol

Step 2: Use the balanced equation to determine the moles of sulfuric acid (H2SO4) that react with the moles of sodium hydrogen carbonate (NaHCO3).

From the balanced equation, we can see that the mole ratio between H2SO4 and NaHCO3 is 1:1. This means that for every 1 mole of NaHCO3, 1 mole of H2SO4 is required.

So, the moles of H2SO4 is also 0.01 mol.

Step 3: Convert the volume of the solution to liters.

The volume of the solution is given as 30.00 mL. To convert it to liters, divide by 1000 (since 1 L = 1000 mL):
30.00 mL / 1000 = 0.0300 L

Step 4: Calculate the molarity (M).

The molarity (M) is defined as moles of solute divided by liters of solution. In this case, we divide the moles of H2SO4 by the volume of the solution in liters:
Molarity = moles / volume

Molarity = 0.01 mol / 0.0300 L ≈ 0.333 M

Therefore, the molarity of the sulfuric acid (H2SO4) solution is approximately 0.333 M.