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December 19, 2014

December 19, 2014

Posted by **v** on Tuesday, December 4, 2012 at 5:51pm.

tan^2 theta -4 = 0

i got theta = arctan 2

is that correct? and if it is how would i write it as a solution?

- trigonmetry -
**Steve**, Tuesday, December 4, 2012 at 6:44pmtheta = arctan2 or arctan -2

because tan^2 = 4, so tan is +/- 2

that's as exact as you can get. Just as pi or sqrt(7) is a perfectly valid number, so is arctan(2)

just be sure to note that since arctan(-2) = pi-arctan(2), the complete solution set is

k*pi+/-Arctan(2)

where Arctan(2) is the principal value.

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