Saturday

August 23, 2014

August 23, 2014

Posted by **Mackenzie** on Tuesday, December 4, 2012 at 5:40pm.

I took the cross product of the 2 equations and got 3i-j-2k

I then set z=0 and got x=5/2 and y=1/2.

I got:

x=5/2 +3t

y=1/2-t

z=-2t

However, the answers are supposed to be:

x=5/2-(3/2)t

y=1/2+(1/2)t

z=t

What is my procedure missing to get there?

- Calculus -
**A.**, Tuesday, December 4, 2012 at 6:09pmI think your method is correct.

You took the cross product of the two vectors of the plane <1,1,1>x<1,-1,2> and got the direction vector v=<3,-1,-2>

You combined the two equations and got (0,5/2,1/2), which gives you the position

There are many different solutions for an equation of a line. So dont think that your answer is wrong.

- Calculus -
**A.**, Tuesday, December 4, 2012 at 6:12pm*oops (5/2,1/2,0) for position

Looking at the answer again,

it looks like they divided the vector by 2

- Calculus -
**Mackenzie**, Tuesday, December 4, 2012 at 6:22pmDo you know why they divided it by 2?

**Related Questions**

Calculus - Find the parametric equations for the line of intersection of the ...

Calculus - Consider the planes given by the equations 2y−2x−z=2 x&#...

Math - Find parametric equations and symmetric equations for the line of ...

vectors - 3 planes; $: x+2y-2z-6=0 %: 2x-y+z+8=0 £: 2x-y+2z+3=0 (a)(i)Find the ...

Vectors - 3 planes; $: x+2y-2z-6=0 %: 2x-y+z+8=0 £: 2x-y+2z+3=0 (a)(i)Find the ...

Math - Intersection of planes - Find the vector equation of the line of ...

maths - geometry - In a space with an orthonormal coordinate system consider the...

Math - intersection of planes - You are given the following two planes: x+4y-3z-...

Calculus - Find parametric equations for the tangent line to the curve with the ...

Calculus - 1. a) Write the vector and parametric equations of the line through ...