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Posted by on Tuesday, December 4, 2012 at 5:26pm.

The normal boiling point of bromine (Br2) is 58.8°C, and its molar enthalpy of vaporization is ΔHvap = 29.6 kJ/mol.

Calculate the value of ΔS when 1.00 mol of Br2(l) is vaporized at 58.8°C.?

  • Chemistry - , Tuesday, December 4, 2012 at 9:46pm

    dG = dH - TdS
    At equilibrium (which you have at the boiling point), dG = 0, then
    0 = dH -TdS
    TdS = dH
    dS = dH/T = ?
    Remember T must be in kelvin; also dH in kJ gives dS in kJ or dH in J gives dS in J.

  • Chemistry - , Friday, October 31, 2014 at 3:26pm


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