Posted by Daisy on Tuesday, December 4, 2012 at 5:11pm.
since sin^2 = 1-cos^2,
1-cos^2 = -2 + 2cos
cos^2 + 2cos - 3 = 0
(cos+3)(cos-1) = 0
cos=1, so x = 0,2pi,4pi,...
why not -3?
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