Posted by Jane on Tuesday, December 4, 2012 at 5:01pm.
Peter has 1200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed area?

Math  Ms. Sue, Tuesday, December 4, 2012 at 5:06pm
It's a square.

Math  Jane, Tuesday, December 4, 2012 at 5:15pm
So what exactly would the answer be? im confused..

Math  Ms. Sue, Tuesday, December 4, 2012 at 5:19pm
1200/4 = 300 yards on each side.
A = 300 * 300
A = ?

Math  Jane, Tuesday, December 4, 2012 at 5:20pm
Oh i see now! Ok thank you!

Math  A., Tuesday, December 4, 2012 at 5:26pm
Finding the Absolute Area....
Area of the fence:
A=x*y
Perimeter of the fence
2x+2y=1200
Then, you solve for one variable
2x=12002y
x=600y < plug this back into the Area function and you will get
A=(600y)y
A=600yy^2
And I believe you can set that equal to zero
y^2+600y=0
Then you use the quadratic formula
b=600
a=1
so y= 600/(2)*(1)
y=300
That'll give you one side, then plug it back to perimeter equation to get x. Hope this is right!

Math  Ms. Sue, Tuesday, December 4, 2012 at 5:32pm
You're welcome.
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