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April 19, 2014

April 19, 2014

Posted by **matt** on Tuesday, December 4, 2012 at 4:11pm.

- math -
**Steve**, Tuesday, December 4, 2012 at 4:26pmif the near ship is at distance a,

the distance between the ships is b,

a/40 = cot67°

(a+b)/40 = cot22°

b = 40(cot22°-cot67°) = 82.02

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