Posted by kristina on Tuesday, December 4, 2012 at 3:41pm.
3+√(2x+2) = x
√(2x+2) = x-3
2x+2 = (x-3)^2
2x+2 = x^2-6x+9
x^2-8x+7 = 0
(x-1)(x-7) = 0
x = 1 or 7
check for extraneous roots:
3+√(2+2) = 3+2 = 5 nope
3+√16 = 3+4 = 7 ok
so, x=7 is the only solution
x=1 is the solution using the -√
3-√4 = 1
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