Posted by azmeena on .
find the horizontal asymptote of f(x)= 8x/2x^2+1

math 
Steve,
as x gets huge, all but the highest powers don't matter, so you have
f(x) > 8x/2x^2 = 4/x > 0
whenever the denominator is a higher power than the numerator, the asymptote is y=0.