Posted by azmeena on Tuesday, December 4, 2012 at 2:18pm.
find the horizontal asymptote of f(x)= 8x/2x^2+1

math  Steve, Tuesday, December 4, 2012 at 2:47pm
as x gets huge, all but the highest powers don't matter, so you have
f(x) > 8x/2x^2 = 4/x > 0
whenever the denominator is a higher power than the numerator, the asymptote is y=0.
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