Posted by Anamika on .
if tangent to the curve y=2sinx +sin2x are drawn at p(x=60degree) then find the area of the quadrilateral formed by the tangent the normal at P and the coordinate axis

maths plse help me.. 
Steve,
y'(x) = 2cosx+2cos2x
y'(pi/3) = 11 = 0
y(pi/3) = √3+√3/2 = 3√3/2
so, we have the axes, and the lines y=3√3/2 and x=pi/3
the rectangle has area pi√3/2 
maths plse help me.. 
Anamika,
plse read the question carefully...its find the area of quadrilateral not the rectangle.

maths plse help me.. 
Steve,
it happens that the quadrilateral formed by those lines is a rectangle.
the tangent is horizontal and the normal is vertical.