if a cube of 10 X 10 X 10 is slices into 1 X 1 X 1 cubes and then rearranged as earlier.if the outer most layer of cubes fall, how many cubes fall and how much are left....?

9x9x9 cubes are left and

1000 - 9^3 fall.,o

plse explain me again..

To determine the number of cubes that fall and how many are left, we need to consider the structure of the cube and the number of cubes in each layer.

First, let's clarify the structure of the cube. The original cube has dimensions of 10 x 10 x 10, meaning it consists of 10 layers, each with 10 x 10 = 100 cubes.

When each layer of the cube is sliced into 1 x 1 x 1 cubes, the resulting cube will have dimensions of 10 x 10 x 10 as well. However, the size of each cube will be significantly smaller, so there will be 10 x 10 x 10 = 1000 cubes in total.

Now, let's determine how many cubes make up the outermost layer. Since the original cube has 10 layers, the outermost layer will consist of the top face (10 x 10 cubes), the bottom face (10 x 10 cubes), and the surrounding four edges (4 x 10 cubes each, totaling 40 cubes). Therefore, the outermost layer consists of 10 x 10 + 10 x 10 + 40 = 200 cubes.

If the outermost layer of cubes falls, we subtract the 200 cubes from the original 1000 cubes in the rearranged cube, leaving us with 1000 - 200 = 800 cubes left.

In conclusion, if the outermost layer of cubes falls after rearranging the original cube, 200 cubes will fall, and 800 cubes will be left.