Wednesday
April 1, 2015

Homework Help: physics

Posted by toby on Tuesday, December 4, 2012 at 2:04am.

A 2.00 kg frictionless block is attached to a horizontal spring as shown. At t = 0, the position x = 0.225 m, and the velocity is 4.25 m/s toward the right in the positive x direction. Position x as a function of t is: x = A*cos(ωt ) , where A is the amplitude of motion and ω is the angular frequency discussed Chapter 11 and the notes.

(a) (3 points) What is the spring constant k?
(b) (25 points) Use conservation of energy to compute amplitude A.
(c) (5 points) How much farther from the point shown will the block move before it momentarily comes to rest before turning around?
(d) (4 points) What is the period T of the motion?
(e) (3 points) If the mass of this problem was doubled to 4.00 kg, how would your answer to part (d ) change?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Physics - A block of mass m1=1.6kg, initially moving to the right with a ...
physics - A block rests on a frictionless horizontal surface and is attached to ...
physics - At t = 0 a block with mass M = 5 kg moves with a velocity v = 2 m/s at...
Physics - A block of mass m = 2.00 kg is attached to a spring of force constant...
Physics - A block of mass m = 2.00 kg is attached to a spring of force constant...
physics - In Figure (a), a block of mass m lies on a horizontal frictionless ...
physics - A 280-g wood block is firmly attached to a very light horizontal ...
physics - A 280-g wood block is firmly attached to a very light horizontal ...
Physics - A 1.07 kg block slides across a horizontal surface directly toward a ...
phys223 - What is the amplitude of the motion? Remember, at t = 0 a block with ...

Members