Posted by sapna on Tuesday, December 4, 2012 at 2:02am.
a x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )
In this case :
a x ^ 2 + b x + c = a ( x - 0 ) ( x - 2 ) = a x ( x - 2 ) = a ( x ^ 2 - 2 x )
plse explain me again, i didn't get it..
plsee ..i need urgent
If x1 and x2 are two roots of equation
a x ^2 + b x + c =0
then
a x ^ 2 + b x + c = a ( x - x1 ) ( x -x2 )
a
is leading coefficient
That is true for any value of a
example:
3 ( x ^ 2 - 2 x ) = 0
has roots 0 and 2
7 ( x ^ 2 - 2 x ) = 0
has roots 0 and 2
39 ( x ^ 2 - 2 x ) = 0
has roots 0 and 2
etc.
Thank You so much..
Related Questions
Calculus - Which of the following would have a horizontal asymptote of y = b/a? ...
maths - how do i find out the the equation of the line of symmetry for f(x)=ax^2...
Maths: Intergration - The curve with equation y = ax^2 + bx + c passes through ...
maths - If 5x4-14x³+18x²+40x+16=(x²-4x+8)(ax²+bc+c) ...
calc - is the integral of 2x/(x^3-x) =-1/2ln(x+1)+1/2ln(x-1) I got this by doing...
Alg2/Trig - How would I go about solving this equation algebraically? Find the ...
Math (Help This Will Be on My Test Tomorrow!) - y= ax^2+bx-4. How would i find ...
Algebra - Can someone please help me with these algebra problems? The directions...
calculus - Consider the following shaded region. Find the area S of this region ...
Maths - 3 2 If 3x+ax+bx+4 has x+1 as factor and leaves remainder 2 when divided...
For Further Reading
