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Posted by **sapna** on Tuesday, December 4, 2012 at 2:02am.

- maths -
**Bosnian**, Tuesday, December 4, 2012 at 3:15ama x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )

In this case :

a x ^ 2 + b x + c = a ( x - 0 ) ( x - 2 ) = a x ( x - 2 ) = a ( x ^ 2 - 2 x )

- maths -
**sapna**, Tuesday, December 4, 2012 at 7:39amplse explain me again, i didn't get it..

- maths -
**sarika**, Tuesday, December 4, 2012 at 9:23amplsee ..i need urgent

- maths -
**Anonymous**, Tuesday, December 4, 2012 at 9:56amIf x1 and x2 are two roots of equation

a x ^2 + b x + c =0

then

a x ^ 2 + b x + c = a ( x - x1 ) ( x -x2 )

- maths -
**Bosnian**, Tuesday, December 4, 2012 at 9:59ama

is leading coefficient

- maths -
**Bosnian**, Tuesday, December 4, 2012 at 10:03amThat is true for any value of a

example:

3 ( x ^ 2 - 2 x ) = 0

has roots 0 and 2

7 ( x ^ 2 - 2 x ) = 0

has roots 0 and 2

39 ( x ^ 2 - 2 x ) = 0

has roots 0 and 2

etc.

- maths -
**sapna**, Tuesday, December 4, 2012 at 11:32amThank You so much..

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