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November 28, 2014

November 28, 2014

Posted by **mikey** on Monday, December 3, 2012 at 10:33pm.

1.)

(radical 3 + i radical 15)(radical 3 - i radical 15)

2.)

8 + 16i / 2i

Thanks again everyone. Any help is appreciated.

- trigonometry -
**Reiny**, Monday, December 3, 2012 at 11:13pm1.

(√3 + i√15)(√3 - i√15)

= 3 - 15i^2

= 3 - 15(-1) = 18

2. I am pretty sure you meant:

(8+16i)(2i)

= (8 + 16i)/(2i) * i/i

= (8i + 16i^2)/(2i^2)

= (8i - 16)/-2

= 8 - 4i

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