Posted by bee on Monday, December 3, 2012 at 10:02pm.
cos4x = cos2x
2cos^2(2x)-1 = cos2x
2cos^2(2x)-cos(2x)-1 = 1
(2cos2x+1)(cos2x-1) = 0
so, cos2x = -1/2 or 1
cos 2pi/3 = cos 4pi/3 = -1/2
cos 0 = 1
as for the identity, I get the feeling there's a typo, because secx appears twice on the right.
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