A satellite orbiting the earth in a circular path stays at a constant altitude of 100 kilometers throughout its orbit. Given that the radius of the earth is 6370 kilometers, find the distance that the satellite travels in completing 70% of one complete orbit.
To find the distance that the satellite travels in completing 70% of one complete orbit, we need to first find the circumference of the satellite's orbit.
The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle.
In this case, the radius of the satellite's orbit is the sum of the radius of the Earth (6370 kilometers) and the altitude at which the satellite is orbiting (100 kilometers). So, the total radius of the satellite's orbit is 6370 + 100 = 6470 kilometers.
Using the formula for the circumference, we can calculate the distance of the satellite's orbit as:
C = 2π * 6470 = 40,688.56 kilometers
Now, we need to find 70% of this distance, which is (70/100) * 40,688.56 = 28,481.99 kilometers.
Therefore, the distance that the satellite travels in completing 70% of one complete orbit is approximately 28,481.99 kilometers.