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Physics URGENT!!!

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The overall length of a piccolo is 30.6 cm. The resonating air column vibrates as in a pipe that is open at both ends. Assume the speed of sound is 343 m/s. (a) Find the frequency of the lowest note a piccolo can play, assuming the speed of sound in air is 343 m/s. (b) Opening holes in the side effectively shortens the length of the resonant column. If the highest note a piccolo can sound is 41.0 kHz, find the distance between adjacent antinodes for this mode of vibration. Assume the speed of sound is 343 m/s

  • Physics URGENT!!! -

    f(n) = nv/2L
    The lowest frequency is
    f1=v/2L =343/2•0.306=560 Hz.
    Distance between adjacent antinodes is λ/2 and λ=v/f
    So λ2=v/2f=343/2•41000 =0.0042 m

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