Posted by **Amanda** on Monday, December 3, 2012 at 12:51pm.

A 600,000-cell bacteria culture is needed for a lab experiment, but you only could purchase 1,000 cells. If the cells double each day, exactly how long will it be before the experiment can be run? Create a model for the bacteria. If the experiment is in seven days, how many cells would be required to purchase today?

- trig -
**Reiny**, Monday, December 3, 2012 at 1:25pm
Since we are doubling, let's use a base of 2

so 1000 (2)^t = 600,000

2^t = 600

log 2^t = log 600

tlog 2 = log 600

t = log 600/log 2

= appr 9.23 days

number of 7 days

600,000 = n 2^6

n = 600000/2^7 = 4687.5

I would purchase 5000

## Answer This Question

## Related Questions

- Math - A colony of bacteria increases according to the law of unihabited growth...
- calculus - 2. The rate of change in the number of bacteria in a culture is ...
- Biology - I'm so horrible at biology so help is appreicated; "The following ...
- Math - (Growth of Cells) Suppose that after t hrs, there are p (t) cells present...
- biology - which of the following types of cells need to make energy to perform ...
- Math - Bacteria can multiply at an alarming rate when each bacteria splits into ...
- MATH :) - 3. In Biology, it is found that the bacteria in a certain culture ...
- Science - How many cell divisions would it take to produce at least 1,000 cells ...
- Pre-Calc/Trig... - is this the correct formula for me to solve this? A bacteria ...
- Math - A certain bacteria doubles the number of its cells every 20 minutes. A ...

More Related Questions