Posted by **Amanda** on Monday, December 3, 2012 at 12:51pm.

A 600,000-cell bacteria culture is needed for a lab experiment, but you only could purchase 1,000 cells. If the cells double each day, exactly how long will it be before the experiment can be run? Create a model for the bacteria. If the experiment is in seven days, how many cells would be required to purchase today?

- trig -
**Reiny**, Monday, December 3, 2012 at 1:25pm
Since we are doubling, let's use a base of 2

so 1000 (2)^t = 600,000

2^t = 600

log 2^t = log 600

tlog 2 = log 600

t = log 600/log 2

= appr 9.23 days

number of 7 days

600,000 = n 2^6

n = 600000/2^7 = 4687.5

I would purchase 5000

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