Tuesday

October 21, 2014

October 21, 2014

Posted by **Anon** on Monday, December 3, 2012 at 11:43am.

integral of x times square root of (2x-1)dx

- Calculus -
**Damon**, Monday, December 3, 2012 at 12:11pmx (2x-1)^.5 dx

u = x

dv = (2x-1)^.5 dx

du = dx

v = (1/3)(2x-1)^1.5

so

(x/3)(2x-1)^(1.5) -(1/3) (2x-1)^1.5 dx

(x/3)(2x-1)^1.5-(1/3)(1/5)(2x-1)^2.5

(1/3)[ x(2x-1)^1.5 - (1/5)(2x-1)^2.5 ]

**Answer this Question**

**Related Questions**

Calculus - Evaluate integral of x times the square root of (x-4) dx I got u-(8u...

Calculus - Evaluate the integral. The integral from 0 to the square root of 2 ...

Calculus - Find the exact area of the region enclosed by the square root of (x...

calculus - how do you solve the integral of 1/[(square root of x)(lnx)] from 2 ...

Calculus - Evaluate the integral from 0 to 24 of the square root of 9+3x dx.

Calculus - evaluate the integral of dx/square root of 9-8x-x^2

Calculus - Evaluate the integral. The integral from the square root of three ...

Calculus - Evaluate the integral from [(2/square rt 2),0] of dx/sqaure root of (...

Calculus - I'd really like some help in solving an integral. ʃ 1/ √x...

Math - Just need some help... Directions: Multiply or raise to the power as ...