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December 22, 2014

December 22, 2014

Posted by **Anon** on Monday, December 3, 2012 at 11:29am.

I got u-(8u^(3/2) over 3)

Can anyone check this for me?

- Calculus -
**Steve**, Monday, December 3, 2012 at 12:30pmif u^2 = x-4

2u du = dx

x = u^2+4

∫x√(x-4) dx = ∫(u^2+4)u 2u du

= ∫2u^4 + 8u^2 du

= 2/5 u^5 + 8/3 u^3

= u^3 (2/5 u^2 + 8/3)

= (x-4)^(3/2) (2/5 (x-4) + 8/3)

= 2/15 (x-4)^(3/2) (3x+8)

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