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Calculate the pH resulting from the addition of the following:
50mL 0.1M KOH and 50mL 0.1M HBr

  • Chem - ,

    KOH + HBr ==> H2O + NaBr.
    50 x 0.1 = 50 x 0.1 so this is at the exact equivalence point which means that the pH is determined by the hydrolysis of the NaBr salt.
    Neither Na^+ nor Br^- is hydolyzed in H2O solution; therefore, the pH is not changed from neutral H2O so pH = 7.0

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