Posted by simranpreet on Monday, December 3, 2012 at 6:57am.
The number of man-hours that were used were
300 + 285 + 270 + 255 + ... + 15 + 0
Since we can't count the + 0 , (nobody worked that day) ,
we need the number of terms of
300+285 + ... + 15
the left side is an AS where a = 300 , d = -15 , n = ?
when the last term is 15
15 = a + d(n-1)
15 = 300 - 15(n-1)
15 = 300-15m + 15
15n = 300
n = 20
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