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April 18, 2014

April 18, 2014

Posted by **simranpreet** on Monday, December 3, 2012 at 6:57am.

- maths -
**Reiny**, Monday, December 3, 2012 at 9:08amThe number of man-hours that were used were

300 + 285 + 270 + 255 + ... + 15 + 0

Since we can't count the + 0 , (nobody worked that day) ,

we need the number of terms of

300+285 + ... + 15

the left side is an AS where a = 300 , d = -15 , n = ?

when the last term is 15

15 = a + d(n-1)

15 = 300 - 15(n-1)

15 = 300-15m + 15

15n = 300

n = 20

- maths -
**Rich**, Thursday, February 27, 2014 at 2:44amReiny's solution just tells us the max number of days not how many days were actually used.

We know that 15 more days were used than originally planned with the full 300.

300d= the sum of the progression

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