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Posted by on Monday, December 3, 2012 at 12:21am.

How many hours are required for the deposition of 15.0 grams of Al from molten AlCl3 by a current of 15.0 amps?

  • Chemistry - , Monday, December 3, 2012 at 12:46am

    It will require 96,485 coulombs to deposit 27/3 = 9 g Al. Therefore, it will require 96,485 x (15/9) coulombs to deposit 15 g.
    1 C = Amp x sec. You know C and amps solve for seconds.

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