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April 18, 2014

April 18, 2014

Posted by **Joe** on Monday, December 3, 2012 at 12:21am.

- Chemistry -
**DrBob222**, Monday, December 3, 2012 at 12:46amIt will require 96,485 coulombs to deposit 27/3 = 9 g Al. Therefore, it will require 96,485 x (15/9) coulombs to deposit 15 g.

1 C = Amp x sec. You know C and amps solve for seconds.

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