Using the accurate concentration that you measured in Part A (which is 14.77 ml), calculate the mass of HCl (in grams) present in a 15.00-mL sample of the acid solution, using proper dimensional analysis
15 mL is not a concn. What is the concn measured in part A? Even with that I don' think the question can be answered without more information.
To calculate the mass of HCl in grams, we need to use the given concentration and volume of the acid solution. Let's break down the steps to solve this using dimensional analysis:
Step 1: Write down the given values:
- Concentration (C) = 14.77 mL
- Volume (V) = 15.00 mL
Step 2: Determine the conversion factor between mL and grams.
To convert mL to grams, we need to know the density of the substance. Since the density of HCl is not provided, we will assume it is 1 g/mL.
Step 3: Set up the dimensional analysis calculation.
To solve for the mass (M), we can use the formula:
M = C * V * conversion factor
where the conversion factor is the density of HCl (1 g/mL).
Step 4: Perform the calculation.
M = 14.77 mL * 15.00 mL * 1 g/mL
Step 5: Simplify and calculate the result.
M = 221.55 g
Therefore, the mass of HCl present in a 15.00-mL sample of the acid solution is 221.55 grams.