your calculator gave you 47.80.. or 48°
then angle C = 180-35-48 = 97 , you had that correct
c/sin97 = 7.2/sin35
c = 7.2sin97/sin35
So triangle ABC is such that
a= 7.2 --- given
b = 9.3 -- given
c = 12.5
Angle A = 35 -- given
Angle B = 48
Angle C = 97
but remember the sine is positive in quadrants I or II
so angle B could also have been 180-48 or 132 °
so c/sin48 = 7.2/sin35
c = 7.2sin48/sin35 = 9.3
so angle C = 180-132-35 = 13°
then c/sin13 = 7.2/sin35
c = 7.2sin13/sin35 = 2.8
B = 132°
C = 13°
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