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October 1, 2014

Homework Help: Math (trigonometry)

Posted by Sammy on Sunday, December 2, 2012 at 9:30pm.

How do you get the second triangle when you have an ambiguous case of sine law? For example, if you are given the following information for a triangle:

a = 7.2 mm, b = 9.3 mm, <A = 35

I can solve for one triangle:

Find <B, <C, side c.

<B:
sinB/9.3 = sin35/72
sinB = 9.3sin35/7.2
B = sin^-1 (9.3sin35/7.2)
B = 48

<C:
180-35-48 = 97

Side c:
c/sin97 = 7.2/sin35
c = 7.2/sin97/sin35
c = 12.5

How do you find and solve for the second one?

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