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Posted by on Sunday, December 2, 2012 at 8:56pm.

An airplane is flying at an elevation of 5150 ft, directly above a straight highway. Two motorists are driving cars on the highway on opposite sides of the plane, and the angle of depression to one car is 35° and to the other is 55°. How far apart are the cars? (Round your answer to the nearest foot.)

  • trigonometry - , Sunday, December 2, 2012 at 9:54pm

    Did you make a sketch?
    According to mine

    distance of first car:
    tan 35 = 5150/x
    x = 5150/tan35
    distance for 2nd car:
    tan 55 = 5150/y
    y = 5150/tan55

    total distance between two cars
    = x + y
    = 5150/tan35 + 5150/tan55 = appr 10961 feet

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