Posted by Cristian on Sunday, December 2, 2012 at 7:32pm.
231 A x 6.3 sec = about 1,500 Coulombs but you need to do it more accurately.
96,485 coulombs will oxidize 1/2 mol Pb which is 207.2/2 = 103.6 g Pb. The amount of Pb deposited will be
103.6 x (1,500/95,485) = ? g Pb.
Thanks!
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