Posted by **Mike** on Sunday, December 2, 2012 at 7:23pm.

What would the LCD be between x^2, 4x, and 6? Here is the problem: 1/x^2+3/4x-5/6

- Math -
**Reiny**, Sunday, December 2, 2012 at 9:26pm
Do it just like you would with numbers

x^2 = x*x

4x = 2*2*x

6 = 2*3

we will need x*x

look at the second set of factors

we will need 2*2*x , but we already have an x

so far we need

2*2*x*x

look at the last group

we will need a 2*3

but we already have the 2, so just include a 3

LCD = 2*2*3*x*x = **12x^2**

notice that 12x^2 divides evenly by each of the other denominators

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