How many grams of CuCl2 are required to prepare 1270. g of a 1.75% (by mass) CuCl2 solution?

Never mind. I got it

To find out how many grams of CuCl2 are required to prepare a 1.75% CuCl2 solution, we can use the following formula:

Mass of CuCl2 = (Percentage of CuCl2 / 100) × Mass of solution

Given:
Percentage of CuCl2 = 1.75%
Mass of solution = 1270 g

Step 1: Convert the percentage to a decimal:
1.75% = 1.75/100 = 0.0175

Step 2: Substitute the values into the formula and calculate:
Mass of CuCl2 = (0.0175) × 1270 g
Mass of CuCl2 = 22.225 g

Therefore, to prepare 1270 g of a 1.75% CuCl2 solution, you would need 22.225 grams of CuCl2.