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Posted by **Jacqueline** on Sunday, December 2, 2012 at 6:43pm.

What is the magnitude of the single

straight-line displacement that the pirate could have taken to reach the treasure?

Answer in units of m

- Physics... -
**Shyamala Manjunath**, Tuesday, December 4, 2012 at 11:23pmHere's what you know,

Dy = 23.5 m, and Dx = 2.7m.

Use the formula

d = (Dx^2 + Dy^2)^ (1/2)

d = (23.5^2 + 2.7^2)^((1/2) = 23.65m

d = 24m (significant digits).

Since they have only asked for magnitude, its 24m.

If they ask for direction then,

theta = tan-1( Dy / Dx )

= tan-1( 23.5 / 2.7)

theta = 83.4 deg or 83 deg (significant digits)

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