Posted by **Shelly** on Sunday, December 2, 2012 at 6:12pm.

Question: A(n) 3.17 m long pendulum is released from

rest when the support string is at an angle of 38.6 degrees with the vertical.

The acceleration of gravity is 9.8 m/s2 .

What is the speed of the bob at the bottom

of the swing?

Answer in units of m/s

What I did:

y=3.17cos38.6 = 1.968297399

h=3.17m-1.968297399m =1.20170261m

v^2 =2(9.8)(1.20170261) =23.55337116

sqrt(23.55337116) =4.85318155

what did I do wrong and how do I fix it? thanks

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