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March 3, 2015

March 3, 2015

Posted by **Karina** on Sunday, December 2, 2012 at 4:46pm.

(4 points) If the water level in the bowl is h cm deep, find the radius of the surface of the water as a function of h.

(6 points) The water level drops at a rate of 0.1 cm per hour. At what rate is the radius of the water decreasing when the depth is 5 cm?

- Calculus -
**Steve**, Sunday, December 2, 2012 at 6:41pmdraw a vertical cross-section of the bowl. Pick a point H on the vertical axis at height h from the bottom. If P is a point on the rim of the bowl, HP = 10. The radius at H is

(10-h)^2 + r^2 = 10^2

r = √(100-(10-h)^2)

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