May 25, 2016

Homework Help: chemistry

Posted by ciaociao on Sunday, December 2, 2012 at 4:36pm.

A galvanic cell consists of a Mn/Mn^2+ electrode (E = -1.18v) and a Fe/Fe^2+ electrode (E = -0.44v). Calculate the ratio [Mn2+]/[Fe2+] if E_cell = .78v at 25C.

I know to use the nernst eq.
E_cell = E_cell - RT/nF * ln(Q)
where Q is the ratio I'm looking for and I a know all of the other #s except for how to find E_cell?

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