math
posted by brad on .
solve the following inequality.
(x3)^2/(x^24)is greater than or equal to 0.

sketch y = (x3)^2 /((x2)(x+2) )
your solution will be all the x's when the graph is above the xaxis
I can see it there is a zero at x = 3
and there are 2 vertical asymptotes at
x = 2 , and x = 2
How about thinking about this intuitively
the numerator is always ≥ 0, since we squared something
Also we can see that x^2  4 is negative for values of x between 2 and 2, and x cannot be +2 or 2
so it looks like the expression is above the xaxis for x > 2 OR x < 2 
how do you write that in interval notation?