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December 20, 2014

December 20, 2014

Posted by **brad** on Sunday, December 2, 2012 at 4:24pm.

(x-3)^2/(x^2-4)is greater than or equal to 0.

- math -
**Reiny**, Sunday, December 2, 2012 at 4:42pmsketch y = (x-3)^2 /((x-2)(x+2) )

your solution will be all the x's when the graph is above the x-axis

I can see it there is a zero at x = 3

and there are 2 vertical asymptotes at

x = 2 , and x = -2

How about thinking about this intuitively

the numerator is always ≥ 0, since we squared something

Also we can see that x^2 - 4 is negative for values of x between -2 and 2, and x cannot be +2 or -2

so it looks like the expression is above the x-axis for x > 2 OR x < -2

- math -
**brad**, Sunday, December 2, 2012 at 4:50pmhow do you write that in interval notation?

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