Posted by **Emily** on Sunday, December 2, 2012 at 3:20pm.

A 2.24 kg mass on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.45 N/m. The mass is displaced 3.06 m to the right from its equilibrium position and then released, which initiates simple harmonic motion. How many times does the mass oscillate in 24.2 s?

- physics -
**Jennifer**, Monday, December 3, 2012 at 8:10pm
First, find the equations that are pertinent to the problem.

F(spring) = -k*x

where F(spring) is the force on a spring, k is the spring constant, and x is the displacement.

w = (k/m)^1/2

where w is the angular acceleration, m is the mass of the spring

T = 2*PI/w

where T is the period of oscillation

w = (4.45/2.24)^0.5

T = 2*PI/w

The number of times the mass will oscillate in 24.2 s is 24.2/T

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