Wednesday

August 20, 2014

August 20, 2014

Posted by **dt** on Sunday, December 2, 2012 at 12:08pm.

Can someone help me find the first and second derivatives please!

- calculus quick question -
**Reiny**, Sunday, December 2, 2012 at 12:42pmwrite it as

g(x) = (1 - 4x^2)^(1/2)

g ' (x) = (1/2)(1 - 4x^2)^(-1/2) (-8x)

= -4x(1 - 4x^2)^(-1/2)

now by the product rule

g '' (x)

= (-4x)(-1/2)(1-4x^2)^(-3/2) (-8x)- 4(1 - 4x^2)^(-1/2)

= (-16x^2)(1-4x^2)^(-3/2) - 4(1 - 4x^2)^(-1/2)

= -4(1 - 4x^2)^(-3/2) [ 4x^2 - (1-4x^2) ]

= -4(1-4x^2)^(-3/2) (4x^2 + x - 2)

= -4( 1-4x^2)^(-3/2)

or

= -4/(1 - 4x^2)^(3/2)

**Related Questions**

calculus - Find the first and second derivatives of the function. h(x) = sqrt x^...

calculus - derivatives - can you please find the first 5 derivatives for: f(x...

math,algebra,help - Directions are simplify by combining like terms. x radiacal ...

Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...

Calculus: Derivatives - I'm having trouble understanding what derivatives in ...

Calculus - Find the first and second derivatives of the given functions. y=¡î(x...

Calculus - find the derivatives of the given functions. g(t)=sqrt t(1+t)/t^2 ...

math - I studied derivatives before, but kind of forgot them all, is there a ...

Derivatives - I have gotten so many different responses from mine on this ...

calculus - PLEASE HELP Find the first and second derivatives of the function. y...