Posted by alice on Sunday, December 2, 2012 at 11:29am.
Could someone explain how to find which months during the year the maximum/minimum points occur for this problem occurs? I think it's around May and Oct, but I don't get how to determine that on the graph
The National Oceanic and Atmospheric Administration (NOAA) has been measuring atmospheric
carbon dioxide concentations (in parts per million) at Mauna Loa, Hawaii since 1958. The data
closely follow the pattern H(t) = 0.013t2 + 0.81t + 316 + 3.5 sin 2πt, where t = 0 represents the
year 1960. (Complete dataset available at ftp://ftp.cmdl.noaa.gov/ccg/co2/trends/c…
1. Explore the CO2 concentration model for the period 1960 – 1962.
a) Graph H for 0 ≤ t ≤ 3 and 300 ≤ H ≤ 340
d) When during the year do the maximum and minimum occur?

Math  alice, Sunday, December 2, 2012 at 11:33am
The formula should actually be: H(t) = 0.013t2 + 0.81t + 316 + 3.5 sin 2πt

Math  alice, Sunday, December 2, 2012 at 11:34am
H(t) = 0.013t^2 + 0.81t + 316 + 3.5 sin 2πt
Ah, the formula should have an exponent!

Math  Reiny, Sunday, December 2, 2012 at 12:03pm
I hope you are taking Calculus
H ' (t) = .026t + .81 + 7πcos (2πt)
= 0 for a max or min
7πcos (2πt) + .026t + .81 = 0
Wow, that's a tough one to solve
Let's try Wolfram, one of the best pages for math.
http://www.wolframalpha.com/input/?i=solve+7πcos+%282πt%29+%2B+.026t++%2B+.81+%3D+0
using the first two positive values of
t = .2559 and t = .744
we get
H(.2559) = appr 319.7
H(.744) = appr 312.7
so I would say : .2559(12) = 3 or March of 1960 has a max of 319.7
.744(12) = 8.9 or then end of August of 1960 has a min of 312.7
repeat by taking the next 4 positive solutions from Wolfram's webpage
Without the help of pages such as the link above, solving equations like this are very onerous. Methods such as Newton's Method work, but require lots of tedious steps and lots of patience.
I want you to image doing this 40 years ago, when we had not calculators or the aid of webpages, doing this with only pencil and paper. We did it.

Math  alice, Sunday, December 2, 2012 at 1:21pm
ah, thanks... i'm only taking "liberal arts math", so have only done a little bit of calculus.
how did you get this part?
H(.2559) = appr 319.7
H(.744) = appr 312.7

Math  Reiny, Sunday, December 2, 2012 at 4:04pm
I substituted .2559 and .744 into the original equation.
Make sure the calculator is set to radians, not degrees.
Answer This Question
Related Questions
 Math  Could someone explain how to solve this math problem? I've graphed it, ...
 calculus  there are no examples of this type of problem in my book so if you ...
 Physics  Can someone check if this is correct or not? Listed following are ...
 calculus  (a) Find the critical points of f(x) = x^(1/3)x^(1/5) (b) Determine ...
 Calculus  Determine where the absolute extrema of f(x)=3(x^2)+7x on the ...
 Math  Can someone help me with these questions? 1.What are the maximum and ...
 statistics  Suppose that the number of accidents occurring in an industrial ...
 Please check my Calculus  1. Find all points of inflection: f(x)=1/12x^42x^2+...
 math  I'm having some troubles with these. Thanks in advance. If a>0 find ...
 math  Consider G. Thumb, the leading salesperson for the Moe D. Lawn ...
More Related Questions