Posted by **dt** on Sunday, December 2, 2012 at 11:24am.

lim

y→−1 (sqrt(y^2+8)-3)/y+3

find limit if it exists

please help

- calculus please help -
**Reiny**, Sunday, December 2, 2012 at 11:36am
step #1 in any limit question is to simply sub in your approach value.

If you get a real number answer, that's it, that's your answer, you are done!

lim ( (√(y^2 + 8) - 3)/(y+3) , y -->-1

= ( √9 - 3)/2

= 0/2

= 0

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