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calculus please help

posted by on .

lim
y→−1 (sqrt(y^2+8)-3)/y+3

find limit if it exists
please help

  • calculus please help - ,

    step #1 in any limit question is to simply sub in your approach value.
    If you get a real number answer, that's it, that's your answer, you are done!

    lim ( (√(y^2 + 8) - 3)/(y+3) , y -->-1
    = ( √9 - 3)/2
    = 0/2
    = 0

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