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December 21, 2014

December 21, 2014

Posted by **JORHO** on Sunday, December 2, 2012 at 8:14am.

A=?+4j+4k

B=?+2j+3K

if the angle them 15 deegre

a.) by scalar product

b.) by vector product

- UNIVERSITY PHYSICS 1 -
**drwls**, Sunday, December 2, 2012 at 9:47amAre the two ? symbols the same numerical i component, or are they different? You have one equation in each case and can only have one unknown.

If the ? components are x, the scalar product is

A*B = x^2 + 8 + 12 = x^2 + 20

and it also equals

|A||B|cos15 = sqrt(x^2+16+16)*sqrt(x^2+4+9)cos15

In principle, you could now solve for x^2, but it would be messy.

x^2 + 20 = sqrt[(x^2+32)(x^2+13)]*0.9659

- UNIVERSITY PHYSICS 1 -
**jorho**, Sunday, December 2, 2012 at 11:06pmsame i

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