Homework Help: chemistry

Posted by paul on Saturday, December 1, 2012 at 11:33pm.

At 25°C the vapour pressure of pure pentane is 511 torr and that of hexane is 150. torr.
What is the mole fraction of pentane in a pentane-hexane solution that has a vapour pressure of 333 torr at 25°C?

chemistry - DrBob222, Sunday, December 2, 2012 at 12:50am
ppen = Xpen*P^o_pentane
phex = Xhex*P^o_hexane

(511*Xpen) + (150*Xhex) = 333
(511*Xp) + 150(1-Xp) = 333
Solve for Xpentane and Xhexane.

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