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At 25°C the vapour pressure of pure pentane is 511 torr and that of hexane is 150. torr.
What is the mole fraction of pentane in a pentane-hexane solution that has a vapour pressure of 333 torr at 25°C?

  • chemistry -

    ppen = Xpen*Popentane
    phex = Xhex*Pohexane

    (511*Xpen) + (150*Xhex) = 333
    (511*Xp) + 150(1-Xp) = 333
    Solve for Xpentane and Xhexane.

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