Friday

October 24, 2014

October 24, 2014

Posted by **Elizabeth** on Saturday, December 1, 2012 at 7:20pm.

Answer in N/m

- PLEASE HELP!! PHYSICS -
**drwls**, Saturday, December 1, 2012 at 7:46pmThe increase in potential energy in stretching from 0.13 to 0.22 m equals the decrease in kinetic energy of the metal sphere. That will let you solve for the spring constant k.

k [(.22)^2 -(.13)^2] = (m/2)[(5.95)^2 - (4.75)^2]

You know the mass m, so solve for k.,

**Answer this Question**

**Related Questions**

physics - A 0.67-kg metal sphere oscillates at the end of a vertical spring. As ...

physics - A 0.67-kg metal sphere oscillates at the end of a vertical spring. As ...

Physics - A 0.56-kg metal sphere oscillates at the end of a vertical spring. As ...

Physics(Please respond) - A 0.33-kg metal sphere oscillates at the end of a ...

physics - An unstrained horizontal spring has a length of 0.33 m and a spring ...

physics - In a room that is 2.13 m high, a spring (unstrained length = 0.30 m) ...

phyics - An object on a vertical spring oscillates up and down in simple ...

phyics - An object on a vertical spring oscillates up and down in simple ...

Physics - In a room that is 2.69 m high, a spring (unstrained length = 0.28 m) ...

physics - In a room that is 2.78 m high, a spring (unstrained length = 0.30 m) ...