precalculus
posted by amaa on .
Find all solutions of the system of equations. (If there is no solution, enter NO SOLUTION.)
4x^2− 27y^3 = 35
8x^2+54y^3= 74

divide the second equation by 2
and the two equations are
4x^2 − 27y^3 = 35
4x^2 + 27y^3 = 37
 add
8 x^2 = 72
x^2 = 9
x = +/ 3
if x = + 3
36 27 y^3 =35
27 y^3 = 1
y^3 = 1/27
y = 1/3
so (3,1/3) would be a solution
same solution for y