(3 - 5i) and (3+5i)
therefore divide by product(x-3+5i) and (x-3-5i)
(x^2 - 6 x + 34)
so do long division
x^2 - 6 x + 34
which is (x^2-3x-40) whew, no remainder
find the two zeros of that
x = [ 3 +/- sqrt (9+160)]/2
= -5 and 8
so in the end
That was fun :)
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