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November 26, 2014

November 26, 2014

Posted by **Heather** on Saturday, December 1, 2012 at 5:50pm.

h(x)=x^4-9x^3+12x^2+138x-1360

zero:3-5i

enter the remaining zeros of f

please show work

- calculus -
**Damon**, Saturday, December 1, 2012 at 6:16pm(3 - 5i) and (3+5i)

therefore divide by product(x-3+5i) and (x-3-5i)

or

(x^2 - 6 x + 34)

so do long division

x^4-9x^3+12x^2+138x-1360

-------------------------

x^2 - 6 x + 34

which is (x^2-3x-40) whew, no remainder

find the two zeros of that

x = [ 3 +/- sqrt (9+160)]/2

= [3+/-13]/2

= -5 and 8

so in the end

-5

+8

-3-5i

-3+5i

- calculus -
**Damon**, Saturday, December 1, 2012 at 6:17pmThat was fun :)

- typo -
**Damon**, Saturday, December 1, 2012 at 7:18pm-5

+8

3-5i

3+5i

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