Posted by Heather on Saturday, December 1, 2012 at 5:50pm.
use the given zeros to find the remaining zeros of the function
h(x)=x^49x^3+12x^2+138x1360
zero:35i
enter the remaining zeros of f
please show work

calculus  Damon, Saturday, December 1, 2012 at 6:16pm
(3  5i) and (3+5i)
therefore divide by product(x3+5i) and (x35i)
or
(x^2  6 x + 34)
so do long division
x^49x^3+12x^2+138x1360

x^2  6 x + 34
which is (x^23x40) whew, no remainder
find the two zeros of that
x = [ 3 +/ sqrt (9+160)]/2
= [3+/13]/2
= 5 and 8
so in the end
5
+8
35i
3+5i 
calculus  Damon, Saturday, December 1, 2012 at 6:17pm
That was fun :)

typo  Damon, Saturday, December 1, 2012 at 7:18pm
5
+8
35i
3+5i