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How to work out: The half-life of Indium-116 is 14 seconds. How long will it take for 32g of this isotope to decay to 1.og?
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All of these radionuclide problems are alike (almost). This is done like the charcoal problem above.
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So we did this lab about how we are to measure the half life of the beta decay of indium 116 (the indium 116 is captured by
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To consider the effects of short-lived and long-lived contaminants separately and understand how
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How to figure out half-lives
Half-live of Indium-116 is 14 seconds. How long will it take for 32 grams of this istotopw to decay
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Every 14 seconds, the isotope's mass is halved.
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Half-life
N2O5 dissolved in CCl4 decomposes to give N2O4 and O2. The reaction is first order with a half-life of 1234 seconds.
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Didn't I do this a couple of days ago for you? k = 0.693/t1/2 Substitute and solve for k. ln(No/N) =
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Indium-117 has a half-life of 43 minutes. If you start with 500 grams of indium-117, how much time will it take to have 31.25
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The amount of indium-117 remaining in the sample can be modeled by the equation: A(t) = A(0) *
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a)indium-115 has a half life of 4.5 hours. if you start with a 12.0-mg sample of indium-115, how much will remain after 13.5
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There is a short way and a long way of doing these. The short way is easy if the numbers are right.
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indium-115 has a half life of 4.5 hours, if you start with a 12.0mg sample of indium-115, how much will remain after 13.5 hours
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two ways: remaining=12mg*(1/2)^13.5/4.5 you can do that by putting this in your google search
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The half-life of the Nobelium isotope No^257 is about 23 seconds. 644 seconds (or 28 half-life periods) after the isotope was
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20=A(.5)^-28 A=20(2)^28 put this in your google search engine: 20*2^28=
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N2O5 dissolved in CCl4 decomposes to give N2O4 and O2. The reaction is first order with a half-life of 1234 seconds. How long
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k = 0.693/t<sub>1/2</sub> ln(No/N) = kt Use No = 100 (you can choose any number) N = 100 x 0.011 = ?
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N2O5 dissolved in CCl4 decomposes to give N2O4 and O2. The reaction is first order with a half-life of 1234 seconds. How long
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To solve this problem, we need to use the concept of half-life and the first-order reaction
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N2O5 dissolved in CCl4 decomposes to give N2O4 and O2. The reaction is first order with a half-life of 1234 seconds. How long
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the fraction left after t seconds is (1/2)^(t/1234) so, solve (1/2)^(t/1234) = 0.011 t = 8028.84
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