Saturday

December 20, 2014

December 20, 2014

Posted by **john daniel** on Saturday, December 1, 2012 at 11:10am.

- physics -
**drwls**, Saturday, December 1, 2012 at 1:11pmThey will pass when the distances traveled are equal.

15 t = (a/2)(t-2)^2 = (t-2)^2

Solve for t, which is measured from the time the 15 m/s car goes by the station.

t^2 -4t +4 = 15 t

t^2 -19t +4 = 0

t = (1/2)[19 +sqrt345) = 18.79 s

Both cars will have travelled 282 m at that time

**Answer this Question**

**Related Questions**

Physics - An automobile moving at a constant velocity of 15m/s passes a gasoline...

Physics - An automobile moving at a constant velocity of 25m/s passes a gasoline...

physics - an automobile moving at a constant velocity of 50 ft/sec passes a ...

physics - An automobile moving at a constant velocity of 15 m/s passes a ...

physics - 1.The speed of a train increased from 15 mi/hr to 25 mi/hr in a ...

PHYSICS - The density of gasoline is 730 kg/m^3 at 0'C. One gallon of gasoline ...

PHYSICS - The density of gasoline is 730 kg/m^3 at 0'C. One gallon of gasoline ...

Physics - Could you please check my answers and units. Thanxs! 1. An automobile ...

Physics - Having trouble determ the formulas for the follow problems. 2. If an ...

Physics - Could you please check my answers and units.Also, help me with 3 and 4...