Two soccer players start from rest, 41 m apart. They run directly toward each other, both players accelerating. The first player’s acceleration has a magnitude of 0.55 m/s2. The second player’s acceleration has a magnitude of 0.43 m/s2. (a) How much time passes before the players collide? (b) At the instant they collide, how far has the first player run?
physics - Henry, Monday, December 3, 2012 at 6:01pm
a. a1 = 0.55m/s^2, a2 = 0.43 m/s^2.
d1 + d2 = 41m.
0.5a1*t^2 + 0.5a*t^2 = 41 m
0.275t^2 + 0.215t^2 = 41
0.49t^2 = 41
t^2 = 83.67
t = 9.15 s.
b. d1 = 0.275*(9.15(^2 = 23.0 m.