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college algebra

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1. find the equation of the line with the given properties. Express the equation in general form or slope-intercept form.
perpendicular to the line -3x_y= -27; contains the point (9, -1)
the equation of the line is ?

2. solve the polynomial inequality and then graph the solution set on a real number line. Express the solution set in interval notation.
x^3+x^2+64x+64<0

please show all work

  • college algebra - ,

    in your -3x_y= -27, since the _ is the "shift" of the - sign, I will assume you meant

    -3x-y= -27 and you have a typo. (But then why would it not have been written as 3x + y = 27 ??? , strange)

    anyway, the slope of the given line is -3
    so the slope of the new line must be +1/3
    and the equation has to have the form
    x - 3y = c, where the c has to be found
    but (9,-1) is to be on this new line, so
    9 - 3(-1) = c
    c = 12

    new line , using my assumption, is
    x - 3y = 12

    2. let y = x^3 + x^2 + 64x + 64 , a standard looking cubic
    so x^3+x^2+64x+64<0 must be the part below the x-axis
    let's find the x-intercepts of the zeros of our function
    x^3+x^2+64x+64 = 0
    x^2(x+1) + 64(x+1) = 0
    (x+1)(x^2 + 64) = 0
    one real root: x = -1 and 2 complex roots

    so a quick sketch would show that the curve is above the x-axis for x > -1 , and below for x < -1

    so solution:
    x < -1

    easy to show on a number line

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