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Posted by on Saturday, December 1, 2012 at 7:16am.

Find the area of a cyclic quadrilateral whose 2 sides measure 4 & 5 units, & whose diagonal coincides with a diameter of the circle. Suppose the radius of the circumscribing circle is 2 sq.root of 3 units.

Please include solution. Thanks.

  • solid mensuration - , Saturday, December 1, 2012 at 9:19am

    In a cyclic quadrilateral, the diagonal would be the hypotenuse of two right-angled triangles.
    Clearly if the hypotenuse , in this case the diagonal, is 4√3, then the two given sides of 4 and 5 cannot be sides of the same triangle.
    I made the following sketch
    Quad ABCD in a circle, with BD as the diagonal of 4√3
    AB = 5 and BC = 4
    in triangle ABD
    AD^2 + 5^2 = (4√3)^2
    AD^2 = 48-25 = 23
    AD = √23

    It should also be obvious that the other triangle BCD is congruent to the first one.
    So total area = 2 (1/2)(5)(√23 = 5√23

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